poj1102——LC-Display

模拟题。运用七段数码显示。参考：http://hi.baidu.com/%8E%E1%D0%B3/blog/item/0846471b6ccf8371dab4bd9a.html

#include<iostream>
#include<cstdio>
#include<string>
using namespace std;
char n1[11]={"- -- -----"};                                 //笔画1被数字0,2,3,5,6,7,8,9覆盖
char n2[11]={"|   ||| ||"};                                 //笔画2被数字0,4,5,6,8,9覆盖
char n3[11]={"|||||  |||"};                                 //笔画3被数字0,1,2,3,4,7,8,9覆盖
char n4[11]={"  ----- --"};                                 //笔画4被数字2,3,4,5,6,8,9覆盖
char n5[11]={"| |   | | "};                                 //笔画5被数字0,2,6,8覆盖
char n6[11]={"|| |||||||"};                                 //笔画6被数字0,1,3,4,5,6,7,8,9覆盖
char n7[11]={"- -- -- --"};                                 //笔画7被数字0,2,3,5,6,8,9覆盖
int s;
char dig[100];
int main()
{
	int i,j,len,k;
	while(scanf("%d%s",&s,dig)&&s)
	{
		len=strlen(dig);
		for(i=0;i<len;i++)
		{
			printf(" ");
			int num=dig[i]-'0';
			for(j=0;j<s;j++)
				printf("%c",n1[num]);
			printf("  ");
		}
		printf("\n");
		for(i=0;i<s;i++)
		{
			for(j=0;j<len;j++)
			{
				int num=dig[j]-'0';
				printf("%c",n2[num]);
				for(k=0;k<s;k++)
					printf(" ");
				printf("%c",n3[num]);
				printf(" ");
			}
			printf("\n");
		}
		for(i=0;i<len;i++)
		{
			printf(" ");
			int num=dig[i]-'0';
			for(j=0;j<s;j++)
				printf("%c",n4[num]);
			printf("  ");
		}
		printf("\n");
		for(i=0;i<s;i++)
		{
			for(j=0;j<len;j++)
			{
				int num=dig[j]-'0';
				printf("%c",n5[num]);
				for(k=0;k<s;k++)
					printf(" ");
				printf("%c",n6[num]);
				printf(" ");
			}
			printf("\n");
		}
		for(i=0;i<len;i++)
		{
			printf(" ");
			int num=dig[i]-'0';
			for(j=0;j<s;j++)
				printf("%c",n7[num]);
			printf("  ");
		}
		printf("\n\n");
	}
	return 0;
}